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In this post, I will try to improve your idea about memory in python using the in-built id()
function. For those of you who don't know what id()
is:
The
id()
function returns a unique ID of the object. All objects in python have a unique ID and no 2 different values correspond to the same ID.
So let us begin with a small example:
a = b = 500
print(id(a) == id(b))
Fun fact: In python,
id(a) == id(b)
is analogous toa is b
.
The above code prints True
because python creates the variable b
with the value 500
and then creates a variable a
pointing to the value of b
. This implies that a
and b
are pointing towards the same memory location and hence the same ID.
Now let's raise the bar:
a = 500
b = 500
print(id(a) == id(b))
The above code prints False
because:
- Python creates a variable
a
pointing to the value500
in the memory. - Then, it creates another variable
b
pointing to another value500
(yeah, both 500 are different).
Hence, both have different IDs because both point toward different memory locations.
I hope this isn't confusing because there is more to come. Guess the output for this:
a = 50
b = 50
print(id(a) == id(b))
Some of you may think "This is the previous question with different values. I know the answer is False
" but not so fast.
For small integers (The CPython range is -5 to 256, both inclusive), then integer objects (<class 'int'>
) are shared. This is done entirely to save space. The memory imprint of the console would be significantly larger if these objects weren’t sharing their memory.
So the correct answer is True
Okay, okay. Just one more to go. The last one:
a = 500
id1 = id(a)
a = 500
id2 = id(a)
print(id1 == id2)
Well, even though I am re-declaring the same variable with the same value, the answer is most likely to be False
. I'll explain to you why. When you re-declare a variable in python, the interpreter works in the same way as a declaration. i.e. It entirely deletes the previous existing value and creates a variable with the new value. So when we give a = 500
, the second time the interpreter deletes the previously existing value of a
and creates a new memory location for 500
where a
would point towards. Both of these IDs are most likely different.
SO, the answer is False
.
NOTE: If the above example had a number belonging to the inclusive range -5 to 256, the answer would have been True
. this is because numbers belonging to the inclusive range have a fixed memory location.